Calculate the boiling point of a solution containing `0.61 g` of benzoic acid in `50 g` of carbon disulphide assuming `84%` dimerization of the acid. The boiling point and `K_(b)` of `CS_(2)` are `46.2^(@)C` and `2.3 kg mol^(-1)`.

Answer

`46.333^(@)C`

Explanation

`i=1-(alpha)/(2)=1-(0.84)/(2)=1-0.42=0.58`
`DeltaT_(b)=iK_(b)m=0.58xx2.3xx(0.61)/(122)xx(1000)/(50)=0.1334^(@)." Hence "T_(b)=46..2+0.133=46.333^(@)C`.