An organic liquid A (immiscible with water) when boiled together with water, the boiling point is `90^(@)C` at which the partial vapour pressure of water is 526 mm Hg. The atmospheric pressure is 736 mm Hg. The weight ratio of the liquid and water collected is 2.5 : 1. Calculate the molecular weight of the liquid.

Explanation

To calculate the molecular weight of the organic liquid A, we will follow these steps:

### Step 1: Understand the Given Data
- The boiling point of the mixture is \(90^\circ C\).
- The partial vapor pressure of water at this temperature is \(P_{H_2O}^0 = 526 \, \text{mm Hg}\).
- The atmospheric pressure is \(P_{atm} = 736 \, \text{mm Hg}\).
- The weight ratio of the organic liquid A to water is \(W_A : W_W = 2.5 : 1\).

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