The solubility of a substance in ether is `2.0 xx10^(-3)M` .
The distribution coefficient of the substance in ether - water mixture is 4.
The solubility of the substance in ether is

Options

A. `3.0xx10^(-4)M`
B. `5.0xx10^(-4)M`
C. `6.0xx10^(-4)M`
D. `8.0xx10^(-4)M`

Explanation

To solve the problem, we need to use the concept of the distribution coefficient (K) and the solubility of the substance in ether and water.

### Step-by-Step Solution:

1. **Understanding the Distribution Coefficient (K)**:
The distribution coefficient (K) is defined as the ratio of the concentration of a solute in one solvent to its concentration in another solvent at equilibrium. In this case, it is given by:
\[
K = \frac{[\text{Solubility in Ether}]}{[\text{Solubility in Water}]}
...