Home
Class 12
CHEMISTRY
Henry's law constant for CO(2) in water...

Henry's law constant for `CO_(2)` in water is `1.67xx10^(8) Pa` at `298 K`. Calculate the quantity of `CO_(2)` in `500mL` of soda water when packed under `2.5atm CO_(2)` pressure at `298 K`.

Text Solution

Verified by Experts

`K_(H)=1.67xx10^(8)"Pa, "p_(CO_(2))="2.5 atm"=2.5xx101325Pa`
`"Applying Henry's law, "p_(CO_(2))=K_(H)xx x_(CO_(2))`
`therefore" "x_(CO_(2))=(p_(CO_(2)))/(K_(H))=(2.5xx101325Pa)/(1.67xx10^(8)Pa)=1.517xx10^(-3)," i.e., "(n_(CO_(2)))/(n_(H_(2)O)+n_(CO_(2)))~=(n_(CO_(2)))/(n_(H_(2)O))=1.517xx10^(-3)`
`"For 500 mL of soda water, water present "~="500 mL = 500 g "=(500)/(18)="27.78 moles"`
i.e.,` n_(H_(2)O)="27.78 moles"`
`therefore (n_(CO_(2)))/(27.78)=1.517xx10^(-3)or n_(CO_(2))=42.14xx10^(-3)" mole = 42.14 m mol "=42.14xx10^(-3)xx44g=1.854g.`
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    PRADEEP|Exercise NCERT EXERCISES|50 Videos

  • SOLUTIONS

    PRADEEP|Exercise NCERT (EXEMPLAR PROBLEMS WITH ANSWERS, HINTS AND SOLUTIONS) (MULTIPLE CHOICE QUESTIONS - I)|26 Videos

  • SOLUTIONS

    PRADEEP|Exercise CONCEPTUAL QUESTIONS|41 Videos

  • REDOX REACTIONS

    PRADEEP|Exercise Assertion reason type question|16 Videos

  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (VIII. Assertion-Reason Type Questions)(Type II)|13 Videos

Similar Questions

Explore conceptually related problems

Henry's law constant for CO_(2) in water is 1.6times10^(8)Pa at 298K . The quantity of CO_(2) in 500g of soda water when packed under 3.2 bar pressure at 298K is

Henry's law constant for CO_(2) in water is 2.5xx10^(8)Pa at 298K . Calculate mmole of CO_(2) dissolved in 14g water at 2.5atm pressure at 298K . [Take 1atm=10^(5)N//m^(2) or Pa ]

henry's law constant for CO_(2) in water is 2.5xx10^(8) Pa at 298K calcualte mmole of CO_(2) dissolbed in 144 g water at 2.5 atm pressure at 298K. [take 1 atm =10^(6)(N)/(m^(2)) or Pa]

Henry's law constant of CO_2 in water at 298K is 5/3K bar. IF pressure of CO_2 is 0.01 bar, find its mole fraction.

Henry's law constant for the molality of methane in benzene at 298K is 4.27xx10^(5)mm Hg . Calculate the solubility of methane in benzene at 298 K under 760 mm Hg .

The Henry's law constant for the solubility of N_(2) gas in water at 298 K is 1.0 xx 10^(5) atm . The mole fraction of N_(2) in air is 0.8 . The number of moles of N_(2) from air dissolved in 10 moles of water at 298 K and 5 atm . Pressure is: