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Calculate the osmotic pressure in pascal...

Calculate the osmotic pressure in pascals exerted by a solution prepared by dissolving `1.0g` of polymer of molar mass `185,000` in `450mL` of water at `37^(@)C`.

Text Solution

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`pi=CRT=(n)/(V)"RT"`
Here, number of moles of solute dissolved `(n)=(1.0g)/("185,000 g mol"^(-1))=(1)/("185,000 g mol")`
`"V = 450 mL = 0.450 L, T = "37^(@)C= 37+273=310K`
`R = "8.314 kPa L K"^(-1)"mol"^(-1)=8.314xx1^(3)" pA L K"^(-1)"mol"^(-1)`
Substituting these values, we get
`pi=(1)/(185,000)"mol"xx(1)/(0.45 L)xx8.314xx10^(3)" Pa L K"^(-1)"mol"^(-1)xx310 K=30.96 Pa.`
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