Based on solute `-` solvent interactions, arrange the following in order of increasing solubility in `n-`octane and explain the result. Cyclohexane, `KCl,CHM_(3)OH,CHM_(3)CN`.

Explanation

(i) Cyclohexane and n-octane both are non-polar. Hence, they mix completely in all proportions.
(ii) KCl is an ionic compound while n-octane is non-polar. Hence, KCl will no dissolve at all in n-octane.
(iii) `CH_(3)OH and CH_(3)CN` both are polar but `CH_(3)CN` is less polar than `CH_(3)OH`. As the solvent is non-polar, `CH_(3)CN` will dissolve more than `CH_(3)OH` in n-octane.
Thus, the order of solubility will be `KCl lt CH_(3)OH lt CH_(3)CN lt "Cyclohexane."`