If the solubility product of `CuS` is `6xx10^(-16)`, calculate the maximum molarity of `CuS` in aqueous solution.

Explanation

Maximum molarity of CuS in aqueous solution = Solubility of Cus in mol `L^(-1)`
If S is the solubility of CuS in mol `L^(-1)`, then
`CuShArrunderset("S")(Cu)^(2+)+underset(S)(S)^(2-),K_(sp)=[Cu^(2+)][S^(2-)]=SxxS=S^(2)`
`therefore" "S^(2)=6xx10^(-6)" or "S=sqrt(6xx10^(-16))=2.45xx10^(-8)" mol L"^(-1)`