Calculate the depression in the freezing point of water when 10 g of `CH_(3)CH_(2)CHClCOOH` is added to 250 g of water. `K_(a)=1.5xx10^(-3),K_(f)=1.86" K kg mol"^(-1)`

Explanation

To solve the problem of calculating the depression in the freezing point of water when 10 g of `CH₃CH₂CHClCOOH` (a carboxylic acid) is added to 250 g of water, we will follow these steps:

### Step 1: Calculate the molar mass of `CH₃CH₂CHClCOOH`
The molecular formula is `C₄H₇ClO₂`. We calculate the molar mass as follows:
- Carbon (C): 12.01 g/mol × 4 = 48.04 g/mol
- Hydrogen (H): 1.008 g/mol × 7 = 7.056 g/mol
- Chlorine (Cl): 35.45 g/mol × 1 = 35.45 g/mol
- Oxygen (O): 16.00 g/mol × 2 = 32.00 g/mol
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