The vapour pressures of pure liquids A B are 450 mm and 700 mm of Hg respectively at 350 K. Calculate the compositon of the liquid mixture if total vapour pressure is 600 mm of Hg. Also find the composition in the Vapour phase.

Explanation

(b) If `x_(A)` is mol fraction of A in liquid phase, then `x_(A)(450)+(1-x_(1))(700)=600 or x_(A)=0.4, x_(B)=0.6.` Hence, `p_(A)=0.4xx450=180mm, p_(B)=0.6xx700=420mm, y_(A)=(180)/(600)=0.3, y_(B)=(420)/(600)=0.7`