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When 2.56 g of sulphur is dissolved in 1...

When 2.56 g of sulphur is dissolved in 100 g of `CS_(2)`, the freezing point of the solution gets lowerd by 0.383 K. Calculate the formula of sulphur `(S_(x))`. [Given `K_(f)` for `CS_(2)`=`3.83` `K kg mol^(-1)]`, [Atomic mass of sulphur=32g `mol^(-1)`]

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(i) `S_(8)`, similar to solved problem 6,
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