Calculate the density of `H_(2)SO_(4)` solution if its molalilty and molarity are 94.5 and 11.5 resoectuvely.

Explanation

Molarity 11.5 means 11.5 moles of `H_(2)SO_(4)` are present in 1 L of the solution. Suppose the density of the solution is `"d g mL"^(-1)`, then 1 L, i.e., 1000 mL of solution has mass = 1000 d g
Thus, 1000 d g of the solution contain `H_(2)SO_(4)=11.5` moles `=11.5xx98g=1127g`
`therefore" Mass of water"=(1000d-1127)g`
`"Molality "=(11.5)/(1000d-1127)xx1000=94.5`
`"or "11500=94.5xx1000d-94.5xx1127" or "94500d=11500+106501.5=118001.5`
`therefore" "d=(118001.5)/(94500)=1.2487"g L"^(-1)`