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The boiling point of benzene rises from...

The boiling point of benzene rises from
`80.1^(@)C` to `13.76g` of biphenyl `(C_(6)H_(5)-C_(6)H_(5))`
is dissolved into 100 g of benzene.
Calculate latent heat of vaporisation of benzene.

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AI Generated Solution

To calculate the latent heat of vaporization of benzene when 13.76 g of biphenyl is dissolved in 100 g of benzene, we can follow these steps: ### Step 1: Determine the change in boiling point (ΔTb) The boiling point of pure benzene is 80.1 °C, and the boiling point after adding biphenyl is 82.4 °C. \[ \Delta T_b = T_{b,\text{final}} - T_{b,\text{initial}} = 82.4 °C - 80.1 °C = 2.3 °C \] ...
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