Find out the osmotic pressure of 0.1 M monobasic acid if pH = 2.0 at `25^(@)C`.

Explanation

`{:(,HA,hArr,H^(+),+,A^(-)),("Initial","C mol L"^(-1),,,,),("At. eqm.",""C-Calpha,,""Calpha,,"Calpha):}`
`" "(alpha = " degree of dissociation")`
`"i.e. "[H^(+)]=C alpha. " But "[H^(+)] = 10^(-2)M`
`therefore" "Calpha =10^(-2) or alpha =(10^(-2))/(C)=(10^(-2))/(0.1)=0.1`
Total number of particles after dissociation `=C-C alpha + C alpha+ C alpha=C(1+alpha)`
`therefore" van't Hoff factor (i)"=(C(1+alpha))/(C)=1+alpha=1+0.1=1.1`
`therefore" Osmotic pressure (P) = i CRT = "1.1xx0.1xx0.0821 xx 298 atm = 2.69 atm.`