Calculate the resulting molarity of the solution that is obtained by adding 5 g of NaOH to 250 ml of `(M)/(4)NaOH` solutoin (density `=1.05 g//cm^(3)`). The density of the resulting solutoin is `1.08 g//cm^(3).`

Explanation

To calculate the resulting molarity of the solution obtained by adding 5 g of NaOH to 250 ml of \( \frac{M}{4} \) NaOH solution, we can follow these steps:

### Step 1: Calculate the mass of NaOH in the original solution
The original solution is \( \frac{M}{4} \) NaOH, which means that there is \( \frac{1}{4} \) mole of NaOH in 1 liter of solution.

1. Molar mass of NaOH = 40 g/mol
2. Mass of NaOH in 1 L = \( \frac{1}{4} \times 40 \, \text{g} = 10 \, \text{g} \)
3. Since we have 250 ml (which is \( \frac{250}{1000} = 0.25 \, \text{L} \)), the mass of NaOH in 250 ml is:
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