Calculate the molarity of a solution of `CaCl_(2)` if on chemical analysis it is found that 200 ml of `CaCl_(2)` solution contains `3.01xx10^(22)` chloride ions.

Explanation

To calculate the molarity of a solution of \( \text{CaCl}_2 \) given that 200 ml of the solution contains \( 3.01 \times 10^{22} \) chloride ions, we can follow these steps:

### Step 1: Determine the number of moles of chloride ions
We know that each formula unit of \( \text{CaCl}_2 \) produces 2 chloride ions (\( \text{Cl}^- \)). Therefore, to find the number of moles of \( \text{Cl}^- \) ions, we can use Avogadro's number, which is \( 6.022 \times 10^{23} \) ions/mole.

Using the formula:
\[
\text{Number of moles of } \text{Cl}^- = \frac{\text{Number of chloride ions}}{6.022 \times 10^{23}}
...