Concentrated aqueous solution of sulphuric acid is `98 %` by mass and has density of `1.80 "g mL"^(-1)`. What is the volume of acid required to make one liter `0.1 M H_(2)SO_(4)` solution ?

Options

A. 5.55 mL
B. 11.10 mL
C. 16.65 mL
D. 22.20 mL

Answer

A

Explanation

`98% H_(2)SO_(4)` by mass means `98 g _(2)SO_(4)` present in 100 g of the solution,
i.e., 100/1.80 mL = 55.5 mL
Also `"98 g "H_(2)SO_(4)="1 mole "H_(2)SO_(4)`
`therefore" Molarity of 98% "H_(2)SO_(4)` solution
`=(1)/(55.5)xx"1000 mol L"^(-1)`
Now, `M_(1)V_(1)=M_(2)V_(2).`
Hence, `(1000)/(55.5)MxxV_(1)="1000 mL"xx0.1M`
`"or "V_(1)=5.55mL`