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6.02xx10^(23) molecules of urea are pres...

`6.02xx10^(23)` molecules of urea are present in `100 ml` of its solution. The concentration of urea solution is -

A

0.02 M

B

0.01 M

C

0.001 M

D

0.1 M

Text Solution

Verified by Experts

The correct Answer is:
B
No. of moles of urea present in 100 mL of solution
`=(6.02xx10^(20))/(6.20xx10^(23))=10^(-3)"mol"`
`therefore` Molar concentration of urea in the solution
`=(10^(-3))/(100)xx1000=10^(-2)M=0.01M`
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