`X_(A)` and `X_(B)` are the mole fraction of A and B respectively in liquid phase `y_(A)` and `y_(B)` are the mole fraction of A and B respective in vapour phase. Find out the slope of straight line if a graph is plotted `(1)/(y_(A))` along Y-axis against `(1)/(x_(A))` along X-axis gives straight line `[p_(A)^(@)` and `p_(B)^(@)` are vapour pressure of pure components A and B].

Options

A. `p_(B)^(@)//p_(A)^(@)`
B. `p_(A)^(@)//p_(B)^(@)`
C. `p_(B)^(@)-p_(A)^(@)`
D. `p_(A)^(@)-p_(B)^(@)`

Answer

A

Explanation

From point 2, page 2/28,
`(1)/(y_(A))=(p_(B)^(@))/(p_(A)^(@))=(1)/(x_(A))+(p_(A)^(@)-p_(B)^(@))/(p_(A)^(@))" "(y=mx+c)`
Hence, plot of `1//y_(A)` along y-axis versus `1//x_(A)`along x-axis will be straight line with slope `=p_(B)^(@)//p_(A)^(@)`.