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The freezing point (in .^(@)C) of a solu...

The freezing point (in `.^(@)C)` of a solution containing `0.1 g` of `K_(3)[Fe(CN)_(6)]` (Mol.wt. 329) in 100 g of water `(K_(f) = 1.86 K kg mol^(-1))` is

A

`-2.3xx10^(-2)`

B

`-5.7xx10^(-2)`

C

`-5.7xx10^(-3)`

D

`-1.2xx10^(-2)`

Text Solution

Verified by Experts

The correct Answer is:
A
`K_(3)[Fe(CN)_(6)]hArr 3K^(+)+[Fe(CN)_(6)]^(3-)`
`therefore I = 4`
`DeltaT_(f)=iK_(f)m=ixxK_(f)xx(w_(2))/(M)xx(1)/(w_(1))xx1000`
`=4xx1.86xx(0.1)/(329)xx(1)/(100)xx1000`
`=0.023 = 2.3xx10^(-2).^(@)C or K`
`T_(f)=0-2.3xx10^(-2).^(@)C=-2.3xx10^(-2).^(@)C`
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The freezing point (in .^(@)C) of a solution containing 0.1g of K_(3)[Fe(CN)_(6)] (Mol. wt. 329 ) in 100 g of water (K_(f) = 1.86 K kg mol^(-1)) is :

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The freezing point (in .^@C ) of solution containing 0.1 g of K_(3)[Fe(CN)_(6)] (molecular weight 329) in 100 g of water (K_(f) = 1.86 K kg mol^(-1)) is

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