Home
Class 12
CHEMISTRY
The correct relationship between molarit...

The correct relationship between molarity (M) and molality (m) is ( d = density of the solution, in `"kg L"^(-1),M_(2)`= molar mass of the solute in `"kg mol"^(-1)`)

A

`M=(md)/(1+nM_(2))`

B

`M=(m)/(1+mM_(2)d)`

C

`M=(1+mM_(2))/(md)`

D

`M=(1+md)/(mM_(2))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the correct relationship between molarity (M) and molality (m), we can follow these steps: ### Step 1: Define Molarity and Molality - **Molarity (M)** is defined as the number of moles of solute per liter of solution. \[ M = \frac{n}{V} \] where \( n \) is the number of moles of solute and \( V \) is the volume of the solution in liters. - **Molality (m)** is defined as the number of moles of solute per kilogram of solvent. \[ m = \frac{n}{W} \] where \( W \) is the mass of the solvent in kilograms. ### Step 2: Relate Molarity to Mass of Solution - The mass of the solution can be expressed using its density (d): \[ \text{Mass of solution} = \text{Density} \times \text{Volume} = d \times 1 \text{ L} = d \text{ kg} \] ### Step 3: Calculate the Mass of Solute - The mass of the solute can be calculated using its molar mass (M2): \[ \text{Mass of solute} = n \times M2 = M \times M2 \] where \( M \) is the number of moles of solute (since we have 1 L of solution). ### Step 4: Calculate the Mass of Solvent - The mass of the solvent can be found by subtracting the mass of the solute from the mass of the solution: \[ \text{Mass of solvent} = \text{Mass of solution} - \text{Mass of solute} = d - M \times M2 \] ### Step 5: Substitute into the Molality Formula - Now, substituting the mass of the solvent into the molality formula: \[ m = \frac{n}{W} = \frac{M}{d - M \times M2} \] ### Step 6: Rearranging for Molarity - Rearranging the equation to express M in terms of m: \[ M = m \times (d - M \times M2) \] - Expanding this gives: \[ M = m \times d - m \times M \times M2 \] - Rearranging further: \[ M(1 + m \times M2) = m \times d \] - Finally, we can express M as: \[ M = \frac{m \times d}{1 + m \times M2} \] ### Conclusion Thus, the relationship between molarity (M) and molality (m) is given by: \[ M = \frac{m \times d}{1 + m \times M2} \]

To find the correct relationship between molarity (M) and molality (m), we can follow these steps: ### Step 1: Define Molarity and Molality - **Molarity (M)** is defined as the number of moles of solute per liter of solution. \[ M = \frac{n}{V} \] where \( n \) is the number of moles of solute and \( V \) is the volume of the solution in liters. ...
Promotional Banner

Topper's Solved these Questions

  • SOLUTIONS

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (II. Multiple Choice Question )|7 Videos
  • SOLUTIONS

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (III. Multiple Choice Question )|13 Videos
  • SOLUTIONS

    PRADEEP|Exercise VALUE BASED QUESTIONS WITH ANSWERS|7 Videos
  • REDOX REACTIONS

    PRADEEP|Exercise Assertion reason type question|16 Videos
  • SOME BASIC CONCEPTS OF CHEMISTRY

    PRADEEP|Exercise Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (VIII. Assertion-Reason Type Questions)(Type II)|13 Videos

Similar Questions

Explore conceptually related problems

The relation between molarity (M) and molality (m) is given by : (p=density of solution (g/mL), M_1 = molecular mass of solute)

The relation between molarity (C ) and molality (m) is given by )d= density of solution, M =molar mass of solute):

The density of 3 M solution of NaCl is 1.25 "g L"^(-1) . The molality of the solution is :

The correct expression relating molality (m), molarity (M), density of solution (d) and molar mass (M_(2)) of solute is :

The expression relating molarity (M) of a solution with its molarity (m) is

Molarity of 1m aqueous NaOH solution [density of the solution is 1.02 g/ml]

PRADEEP-SOLUTIONS-Competition (FOCUS) JEE (Main and Advanced)/Medical Entrance SPECIAL (I. Multiple Choice Question )
  1. The van't hoff factor (i) for a dilute aqueous solution of the strong ...

    Text Solution

    |

  2. The freezing point depression constant for water is -1.86^(@)Cm^(-1).i...

    Text Solution

    |

  3. A 0.1 molal aqueous solution of a weak acid is 30% ionized. If K(f) fo...

    Text Solution

    |

  4. v1newFlow

    Text Solution

    |

  5. The freezing point of benzene decreases by 0.45^(@)C when 0.2 g of ace...

    Text Solution

    |

  6. A 0.004M solution of Na(2)SO(4) is isotonic with a 0.010 M solution of...

    Text Solution

    |

  7. Van't Hoff factors are x,y,z in the case of association, ionisation a...

    Text Solution

    |

  8. For a weak monobasic acid, if pK(a)=4. then at a concentration of 0.01...

    Text Solution

    |

  9. The pH of 1 M solution of a weak monobasic acid (HA) is 2. Then, the v...

    Text Solution

    |

  10. At a certain Hill station, water boils at 96^(@)C. The amount of NaCl ...

    Text Solution

    |

  11. One molal solution of a complex of cobalt chloride with NH(3) in water...

    Text Solution

    |

  12. The depression in freezing point of 0.01 m aqueous CH(3)CooH solution ...

    Text Solution

    |

  13. The average osmotic pressure of human blood is 7.8 bar at 37^(@)C. Wha...

    Text Solution

    |

  14. Solution A contains 7 g/L of MgCl(2) and solution B contains 7 g/L of...

    Text Solution

    |

  15. Two solution (A)containingFecl(3)(aq)and(B) semipermeable membrance as...

    Text Solution

    |

  16. Pure benzene freezes t 5.3^(@)C. A solution of 0.223 g of phenylacetic...

    Text Solution

    |

  17. Consider separate solution of 0.500M C(2)H(5)OH(aq), 0.100M Mg(3)(PO(4...

    Text Solution

    |

  18. Of the following0.10m aqueous solutions,which one will exhibits the la...

    Text Solution

    |

  19. On gram of silver gets distributed between 10cm^(3) of molten zinc and...

    Text Solution

    |

  20. The correct relationship between molarity (M) and molality (m) is ( d ...

    Text Solution

    |