`{:("Column I (Solvent)","Column II "("Value of "K_(f)or K_(b))),("(A) 0.1 M Glucose sol.","(p) Lowest freezing point"),("(B) 0.1 M Sucroe sol.","(q) Highest freezing point"),("(C) 0.1 M "BaCl_(2)" sol.","(r) Lowest osmotic pressure"),("0.1 M "Ca(NO_(3))_(2)" sol.","(s) Highest osmotic pressure"):}`

Answer

To solve the problem, we need to match the solutions in Column I (Solvent) with their corresponding values in Column II (Value of Kf or Kb). The key concepts we will use are the van 't Hoff factor (i), which indicates the degree of dissociation of solutes, and how this affects the freezing point depression and osmotic pressure.

### Step-by-Step Solution:

1. **Identify the van 't Hoff factor (i)**:
- **Glucose (0.1 M)**: Glucose does not dissociate in solution, so \( i = 1 \).
- **Sucrose (0.1 M)**: Sucrose also does not dissociate, so \( i = 1 \).
- **Barium Chloride (BaCl₂, 0.1 M)**: This dissociates into 3 ions: 1 Ba²⁺ and 2 Cl⁻. Thus, \( i = 3 \).
- **Calcium Nitrate (Ca(NO₃)₂, 0.1 M)**: This dissociates into 3 ions: 1 Ca²⁺ and 2 NO₃⁻. Thus, \( i = 3 \).

2. **Determine the effect on freezing point depression (ΔTf)**:
- The depression in freezing point is given by the formula:
\[ \Delta T_f = i \cdot K_f \cdot m \]
Since all solutions have the same molality (assuming molarity = molality), the depression in freezing point will depend solely on the van 't Hoff factor (i).
- Lower \( i \) means a higher freezing point, and higher \( i \) means a lower freezing point.
- Thus, glucose and sucrose (both \( i = 1 \)) will have the highest freezing points, while BaCl₂ and Ca(NO₃)₂ (both \( i = 3 \)) will have the lowest freezing points.

3. **Determine the effect on osmotic pressure (π)**:
- The osmotic pressure is given by the formula:
\[ \pi = i \cdot C \cdot R \cdot T \]
Again, since all solutions have the same concentration, osmotic pressure will also depend on the van 't Hoff factor (i).
- Higher \( i \) means higher osmotic pressure. Therefore, BaCl₂ and Ca(NO₃)₂ will have the highest osmotic pressures, while glucose and sucrose will have the lowest.

4. **Match the columns**:
- **(A) 0.1 M Glucose sol.**: \( i = 1 \) → Highest freezing point (matches with **p**) and lowest osmotic pressure (matches with **r**).
- **(B) 0.1 M Sucrose sol.**: \( i = 1 \) → Highest freezing point (matches with **p**) and lowest osmotic pressure (matches with **r**).
- **(C) 0.1 M BaCl₂ sol.**: \( i = 3 \) → Lowest freezing point (matches with **q**) and highest osmotic pressure (matches with **s**).
- **(D) 0.1 M Ca(NO₃)₂ sol.**: \( i = 3 \) → Lowest freezing point (matches with **q**) and highest osmotic pressure (matches with **s**).

### Final Matches:
- A → p (Lowest freezing point), r (Lowest osmotic pressure)
- B → p (Lowest freezing point), r (Lowest osmotic pressure)
- C → q (Lowest freezing point), s (Highest osmotic pressure)
- D → q (Lowest freezing point), s (Highest osmotic pressure)