The molality of a sulphuric acis solution in which the mole fraction of water is 0.86 is

Explanation

To find the molality of a sulfuric acid solution where the mole fraction of water is 0.86, we can follow these steps:

### Step 1: Determine the mole fraction of sulfuric acid (H2SO4)
The mole fraction of a solute and solvent adds up to 1. Given that the mole fraction of water (solvent) is 0.86, we can calculate the mole fraction of sulfuric acid as follows:

\[ \text{Mole fraction of H2SO4} = 1 - \text{Mole fraction of H2O} \]
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