van't Hoff factor of an electrolyte `A_(2)B_(3)` assuming that it ionizes `75%` in the solution is

Explanation

To find the van't Hoff factor (i) of the electrolyte \( A_2B_3 \) that ionizes 75% in solution, we can follow these steps:

### Step 1: Understand the dissociation of the electrolyte
The electrolyte \( A_2B_3 \) dissociates in the following manner:
\[ A_2B_3 \rightarrow 2A^{3+} + 3B^{2-} \]
This means that for every 1 mole of \( A_2B_3 \) that dissociates, it produces 2 moles of \( A^{3+} \) ions and 3 moles of \( B^{2-} \) ions.
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