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A compound H(2)X with molar weigth of 80...

A compound `H_(2)X` with molar weigth of 80g is dissolved in a solvent having density of `0.4 g mol^(-1)`. Assuming no change in volume upon dissolution, the molarity of a `3.2` molar solution is

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3.2 molar solution contains 3.2 moles of `H_(2)X` in 1000 mL of the solution. As there is no change in volume on dissolution, volume of solvent = 1000 mL.
`"Mass of solvent = 1000 mL "xx0.4"g mL"^(-1)=400g`
= 0.4 kg
`"Molality"=("3.2 moles")/("0.4 kg")="8 mol kg"^(-1)=8m`
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