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MX(2) dissociates into M^(2+) and X^(-) ...

`MX_(2)` dissociates into `M^(2+)` and `X^(-)` ions in an aqeous solution, with a degree dissociation `(alpha)` of 0.5. The ratio of the observed depression of freezing point of the aqueous solution to the value of the depression of freezing point in the absence of ionic dissociation is

Text Solution

Verified by Experts

`underset(1-alpha)(MX_(2))hArrunderset(alpha)(M)^(2+)+underset(2alpha)(2X)^(-)`
`i=1-alpha+alpha+2alpha=1+2alpha`
But `alpha=0.5, therefore i=1+2xx0.5=2`
This is the required ratio.
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