A solution containing 30 g of a non-volatile solute exactly in 90 g water has a vapour pressure of 2.8 kPa at 298 K. Further 18 g of water is then added to the solution, the new vapour pressure becomes 2.9 kPa at 298 K. Calculate
(i) molar mass of the solute.
(ii) vapour pressure of water at 298 K.

A solution containing 30g of a non-volatile non-electrolyte solute exactly in 90g water has a vapour pressure of 2.8 kPa at 298K. Further, 18g of water is then added to solution, the new vapour pressure becomes 2.9kPa at 298K. The solutions obey Raoult's law and are not dilute, molar mass of solute is

A solution containing 30g of a nonvolatile solute in exactly 90g water has a vapour pressure of 21.85 mm Hg at 25^(@)C . Further 18g of water is then added to the solution. The resulting solution has vapour pressure of 22.18 mm Hg at 25^(@)C . calculate (a) molar mass of the solute, and (b) vapour pressure of water at 25^(@)C .

A solution containing 0.5g of a non-volatile solute in 0.2dm^(3) of the solution exerts an osmotic pressure of 44.44 kPa at 300K . Thus, molar mass of the solute is

A solution is prepared by dissolving 10g of non-volatile solute in 200g of water. It has a vapour pressure of 31.84 mm Hg at 308 K. Calculate the molar mass of the solute. (Vapour pressure of pure water at 308K =32 mm Hg)