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Ammonia and oxygen react at high tempera...

Ammonia and oxygen react at high temperature as:
`4NH_(3) (g) + 5O_(2)(g) rarr 4NO(g) + 6H_(2)O (g)`
In an experiment, the rate of formation of `NO` is `3.6 xx 10^(-3) Ms^(-1)`. Calculate (a) the rate of disappearance of ammonia and (b) the rate of formation of water.

Text Solution

Verified by Experts

Rate of reaction `=(1)/(4)(d[NH_(3)])/(dt)=-(1)/(5)(d[NO_(2)])/(dt)=+(1)/(4)(d[NO])/(dt)=+(1)/(6)([H_(2)O])/(dt)`
Rate of disappearance of `NH_(3)`= Rate of formation of `NO=3*6xx10^(-3)" mol "L^(-1)x^(-1)`
Rate of formation of `H_(2)O=(6)/(4)xx` Rate of formation of NO
i.e., `" "(d[H_(2)O])/(dt)=(3)/(2)xx(3.6xx10^(-3)"mol "L^(-1)s^(-1))=5.4xx10^(-3)"mol "L^(-1)s^(-1)`
Alternatively, `(1)/(6)(d[H_(2)O])/(dt)=(1)/(4)(d[NO])/(dt)implies" Rate of formation of "H_(2)O,(d[H_(2)O])/(dt)=(6)/(4)xx(d[NO])/(dt)`
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