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From the concentrations of C(4)H(9)Cl (b...

From the concentrations of `C_(4)H_(9)Cl` (butyl chloride) at different times given below, calculate the average rate of the reaction:
`C_(4)H_(9)Cl +H_(2)Orarr C_(4)H_(9)OH+HCl`
during different intervals of time.
`{:(t//s,0,50,100,150,200,300,400,700,800),([C_(4)H_(9)Cl]//"mol"^(-1),0.100,0.0905,0.0820,0.0741,0.0671,0.0549,0.0439,0.0210,0.017):}`

Text Solution

Verified by Experts

Average rate of reaction in the interval `t_(1)` to `t_(2)=(-"{"[C_(4)H_(9)Cl]_(t_(2))-[C_(4)H_(9)Cl]t_(1)"}")/(t_(2)-t_(1))`
`{:("Time//s",,,[C_(4)H_(9)Cl]//molL^(-1),,,"Time interval",,,"Average Rate "(molL^(-1)s^(-1))),(0,,,0*100,,," "-,,," "-),(50,,,0*0905,,,0-50,,,(-(0-0905-0-100)molL^(-1))/((50-0)s)=1*96xx10^(-4)),(100,,,0*0820,,,50-100,,,(-(0*0820-0*0905)molL^(-1))/((100-50)s)=1*70xx10^(-4)),(150,,,0*0741,,,100-150,,,(-(10*0741-0*0820)molL^(-1))/((150-100)s)=1*58xx10^(-4)),(200,,,0*067,,,150-200,,,(-(0.067-0*074)molL^(-1))/((200-150)s)=1*40xx10^(-4)),(300,,,0*0549,,,200-300,,,(-(0*0549-0*067)molL^(-1))/((300-200)s)=1*22xx10^(-4)" & so on."):}`
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