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The rate of decomposition of NH3 on plat...

The rate of decomposition of `NH_3` on platinum surface, `2NH_(3) (g) overset(Pt) (to) N_(2) (g) + 3H_(2) (g)` is rate `=k` order with `k = 2.5 xx 10^(-4)" mol L"^(-1)" s"^(-1)`. What are the rates of production of `N_2 and H_2`?

Text Solution

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`2 NH_(3)toN_(2)+3 H_(2)," Rate"=-(1)/(2)(d[NH_(3)])/(dt)=+(d[N_(2)])/(dt)=+(1)/(3)(d[H_(2)])/(dt)`
For zero order reaction, rate `=k:.-(1)/(2)(d[NH_(3)])/(dt)=(d[N_(2)])/(dt)=(1)/(3)(d[H_(2)])/(dt)=2*5xx10^(-4)molL^(-1)s^(-1)`
`:." Rate of production of "N_(2)=(d[N_(2)])/(dt)=2*5xx10^(-4)molL^(-1)s^(-1)`
Rate of production of `H_(2)=(d[H_(2)])/(dt)=3xx(2*5xx10^(-4)molL^(-1)s^(-1))=7*5xx10^(-4)molL^(-1)s^(-1)`.
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