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The rate of formation of a dimer in a se...

The rate of formation of a dimer in a second order dimerization reaction is `9.5 xx 10^(-5) mol L^(-1) s^(-1)` at `0.01 mol L^(-1)` monomer concentration. Calculate the rate constant.

Text Solution

Verified by Experts

If the monomer is represented by A, then the reaction is : `2Ato(A)_(2)`
As the reaction is of second order, the rate of reaction will be given by : Rate `=k[A]^(2)`
Rate of reaction `=-(1)/(2)(d[A])/(dt)=+(d[A_(2)])/(dt)=9*5xx10^(-5)molL^(-1)s^(-1)`
`:.9*5xx10^(-5)"mol "L^(-1)s^(-1)=k(0*01"mol "L^(-1))^(2)=kxx10^(-4)("mol "L^(-1))^(2)" or "k=0*95L" mol"^(-1)s^(-1)`
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