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The following rate data were obtained at...

The following rate data were obtained at 303K for the following reaction :
`2A+BtoC+D`
`{:("Experiment",,,[A]//"mol "L^(-1),,,[B]//"mol "L^(-1),,,"Initial rate of formation of "D//"mol "L^(-1)min^(-1)),(I,,,0*1,,,0*1,,,6*0xx10^(-3)),(II,,,0*3,,,0*2,,,7*2xx10^(-2)),(III,,,0*3,,,0*4,,,2*88xx10^(-1)),(IV,,,0*4,,,0*1,,,2*4xx10^(-2)):}`
What is the rate law ? What is the order with respect to each reactant and the overall order ? Also calculate the rate constant and write its units.

Text Solution

AI Generated Solution

To solve the problem, we will follow these steps: ### Step 1: Write the Rate Law Expression The rate law for the reaction \(2A + B \rightarrow C + D\) can be expressed as: \[ \text{Rate} = k [A]^{\alpha} [B]^{\beta} \] where \(k\) is the rate constant, \(\alpha\) is the order with respect to reactant A, and \(\beta\) is the order with respect to reactant B. ...
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