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The initial concentration of N2O5 in the...

The initial concentration of `N_2O_5` in the first order reaction `N_2O_5 to 2NO_2 + 1//2O_2` was `1.24 xx10^(-2) "mol L"^(-1)` at 318 K. The concentration of `N_2O_5` after 60 minutes was `0.20 xx 10^(-2) "mol L"^(-1)`. Calculate the rate constant of the reaction at 318 K.

Text Solution

Verified by Experts

`k=(2.303)/(t)log""([A]_(0))/([A])=(2.303)/(t)log(["N"_(2)"O"_(5)]_(0))/(["N"_(2)"O"_(5)]_(t))=(2.303)/(60" min")log""(1.24xx10^(-2)"mol L"^(-1))/(0.2xx10^(-2)"mol L"^(-1))`
`=(2.303)/(60)log6.2min^(-1)=(2.303)/(60)xx0.7924min^(-1)=0.0304min^(-1)`
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