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A first order reaction has a specific re...

A first order reaction has a specific reaction rate of `10^(-3)" sec"^(-1)`. How much time will it take for 10 g of the reactant to reduce to 2.5 g ? Given `log2=0.301, log4=0.6021,log6=0.778`.

Text Solution

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We know that for a first order reaction, `t=(2.303)/(k)log""(a)/(a-x)`
Here, initial concentration, a = 10 g and concentration left after time t sec. `=2.5" g",i.e.,(a-x)=2.5" g"`
Specific reaction constant `k=10^(-3)" sec"^(-1)`
`:." Time required for the reactant to reduce to "2.5" g "=(2.303)/(10^(-3)s)xxlog""(10)/(2.5)=(2.303)/(10^(-3))xxlog4=(2.303)/(10^(-3))xx0.6021s`
`=1386.6" s"." "["Given "log4=0.6021]`
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