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The rate constant for an isomerisation r...

The rate constant for an isomerisation reaction `Ato B` is `4.5 xx 10^(-3)min^(-1)`. If the initial concentration of A is 1M, Calculate the rate of the reaction after 1 hour.

Text Solution

Verified by Experts

Rate constant in `min^(-1)` shows that it is a reaction of 1st order. Hence, `k=(2.303)/(t)log""([A]_(0))/([A])`
or `4.5xx10^(-5)min^(-1)=(2.303)/(60" min")log""(1)/([A])" or "log[A]=-0.1172=1.8828" or "[A]=" Antilog "1.8828`
`:.[A]=0.7635" mol L"^(-1).` This is the concentration after 1 h.
Rate after `1 h=k[A]=4.5xx10^(-3)xx0.7635" mol L"^(-1)min^(-1)=3.44xx10^(-3)" mol L"^(-1)mil^(-14).`
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