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A reaction is of first order in reactant...

A reaction is of first order in reactant A and of second order in reactant B. How is the rate of this reaction affected when (i) the concentration of B alone is increased to three times (ii) the concentrations of A as well as B are doubled?

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The correct Answer is:
(i) 9 times (ii) 8 times
`r=k[A][B]^(2)=kab^(2)"(i) "r=ka(3" b")^(2)=9" kab"^(2)" (ii) "r=k(2" a")(2" b")^(2)=8" kab"^(2)`.
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