A first order reaction is found to have a rate constant `k=7.39xx10^(-5)s^(-1)`. Find the half life of this reaction.

Answer

`9.38xx10^(3)s`

Explanation

For a first order reaction, `k=(2.303)/(t)log""(a)/(a-x)" ":" ""For "t=t_(1//2),x=a//2`
`t_(1//2)=(2.303)/(k)log""(a)/(a-a//2)=(2.303)/(k)log2=(2.303)/(7.39xx10^(-5)s^(-1))xx0.3010=9.38xx10^(3)s`