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For a first order reaction, it takes 5 ...

For a first order reaction, it takes 5 minutes for the initial concentration of 0.6 mol `L^(-1)` to become `0.4` mol `L^(-1)`. How long in all will it take for the initial concentration to become 0.3 mol `L^(-1)`?

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The correct Answer is:
8.54 min
`a=0.6" mol L"^(-1),(a-x)=0.4" mol L"^(-1),t=5" min "," "k=(2.303)/(5" min")log""(0.6)/(0.4)=0.0811" min"^(-1),`
`0.6" mol L"^(-1)to0.3" mol L"^(-1)"means "t_(1//2).` Hence, `t_(1//2)=(0.693)/(0.0811" min"^(-1))=8.54" min".`
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