The rate constant for first order reaction is 60/s. How much time will it take to reduce the concentration of the reaction to 1/10 of its initial value ?

Answer

`0.0384" s"`

Explanation

`t=(2.303)/(k)log""(a)/(a-x)=(2.303)/(60s^(-1))log""(a)/(a//10)=(2.303)/(60s^(-1))log10=0.0384s`