Rate constant of a first order reaction, A `to` Product is `0.016" min"^(-1)`. Calculate the time required for `80%` of the reaction to be completed.

Answer

`100.6" min"`

Explanation

`t=(2.303)/(k)log""(a)/(a-x)=(2.303)/(0.016" min"^(-1))log""(a)/(a-0.8a)=(2.303)/(0.016)log5=100.6" min"`