A first order reaction has a rate constant of 0.0051 `min^(-1)`. If we begin with 0.10 M concentration of the reactant, What concentration of reactant will remain in solution after 3 hours?

Answer

`0.04" M"`

Explanation

`k=(2.303)/(t)log""([A]_(0))/([A]):.0.0051" min"^(-1)=(2.303)/(3xx60" min")log""(0.10)/([A])`
or `log""(0.10)/([A])=0.3986" or "(0.10)/([A])="Antilog "(0.3986)=2.5" or "[A]=(0.10)/(2.5)=0.04" M"`