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For a reaction, the activation energy is...

For a reaction, the activation energy is zero. What is the value of rate constant at `300 K` if `k=1.6 xx 10^(6)s^(-1)` at 280 K
`(R= 8.31 JK^(-1)mol^(-1))`?

Text Solution

Verified by Experts

The correct Answer is:
`1.6xx10^(6)s^(-1)`
`E_(a)=0:.log""(k_(2))/(k_(1))=0" or "(k_(2))/(k_(1))=1" or "k_(2)=k_(1)`
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