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Given that the temperature coefficient f...

Given that the temperature coefficient for the saponification of ethylacetate by `NaOH` is `1.75`. Calculate the activation energy.

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The correct Answer is:
`42.70" kJ mol"^(-1)`
Temp. coeff. `=(k_(308" K"))/(k_(298" K"))=1.75,i.e.,T_(1)=298" K",T_(2)=308" K"`
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