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A 1st order reaction is 50% complete in ...

A 1st order reaction is `50%` complete in 30 minutes at `27^(@)C` and in 10 min at `47^(@)C`. Calculate
(i) rate constant for the reaction at `27^(@)C` and `47^(@)C`
(ii) energy of activation for the reaction.

Text Solution

Verified by Experts

`k_(27^(@)C)=(0.693)/(30" min")=2.31xx10^(-2)min^(-1),k_(47^(@)C)=(0.693)/(10min)=6.93xx10^(-2)min^(-1)`
`log""(6.93xx10^(-2))/(2.31xx10^(-2))=(E_(a))/(2.303xx8.314)((20)/(300xx320))" or "E_(a)=((log3)2.303xx8.314xx300xx320)/(20)=43.85" kJ mol"^(-1)`
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