For the reaction, `4" NH"_(3)(g)+5" O"_(2)(g) to 2NO(g) + 6H_(2)O(g)`, if the rate expression in terms of disappearance of `NH_(3)" is "-(Delta[NH_(3)])/(Deltat)`, write the rate expression in terms of concentration of `O_(2)` and `H_(2)O`.

Answer

Rate `=-(4)/(5)(Delta[O_(2)])/(Deltat)=(4)/(6)(Delta[H_(2)O])/(Deltat)`

Explanation

`-(1)/(4)(Delta[NH_(3)])/(Deltat)=-(1)/(5)(Delta[O_(2)])/(Deltat)=+(1)/(6)(Delta[H_(2)O])/(Deltat).`