A reaction `2" X" to "Y "+3Z` (e.g., `2NH_(3) to N_(2)+3H_(2)`) is being carried out in a closed vessel. The rate of disappearance of X, `-(Delta[X])/(Deltat)` is found to be `0.066" mol L"^(-1)s^(-1)`. Calculate `(Delta[Y])/(Deltat)" and "(Delta[Z])/(Deltat)`

Answer

`(Delta[Y])/(Deltat)=0.033" mol L"^(-1)s^(-1), (Delta[Z])/(Deltat)=0.099" mol L"^(-1)s^(-1)`

Explanation

`-(1)/(2)(Delta[X])/(Deltat)=(Delta[Y])/(Deltat)=(1)/(3)(Delta[Z])/(Deltat)`