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If the activation enery for the forward ...

If the activation enery for the forward reaction is `150 "kJ mol"^(-1)` and that of the reverse reaction is `260 "kJ mol"^(-1)`. What is the ethalpy change for the reaction ?

A

410 `"kJ mol"^(-1)`

B

`-110" kJ mol"^(-1)`

C

`110" kJ mol"^(-1)`

D

`-410" kJ mol"^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
B
(b) : `DeltaH=E_(f)-E_(b)=150-260" kJ"=-110" kJ"`
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