The decomposition of dimethyl ether leads to the formation of `CH_(4),H_(2),` and `CO` and the reaction rate is given by
Rate `=k[CH_(3)OCH_(3)]^(3//2)`
The rate of reaction is followed by increase in the pressure in a closed vessel , so the rate can also be expressed in terms of the partial pressure of dimethyl either, `i.e., `
Rate `=k[p_(CH_(3)OCH_(3))]^(3//2)`
If the pressure is measured in bar and time in minutes, then what are the units of rate and rate constant ?

Explanation

In terms of pressures, units of rate `="bar "min^(-1)`
Units of `k=("Rate")/([P_(CH_(3)OCH_(3))]^(3//2))("bar min"^(-1))/("bar"^(3//2))="bar"^(-1//2)min^(-1).`