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For the decomposition of azoisopropane t...

For the decomposition of azoisopropane to hexane and nitrogen at 54
K, the following data are obtained.

Calculate the rare constant.

Text Solution

Verified by Experts

`("CH"_(3))_(2)"CH N"="N CH"("CH"_(3))_(2)(g)to"N"_(2)(g)+"C"_(6)"H"_(16)(g)`
`{:("Initial pressure",,," ""P"_(0),,,,0,,,0),("After time t",,,"P"_(0)-"p",,,,"p",,,"p"):}`
Total pressure after time `t(P_(t))=(P_(0)-p)+p+p=P_(0)+p" or "p=P_(t)-P_(0)`
`apropP_(0)" and "(a-x)propP_(0)-p` or substituting the value of p,
`a-xprop P_(0)-(P_(t)-P_(0)),i.e.,(a-x)prop P_(0)-P_(t)`
As decomposition of azoisopropane is a first order reaction,
`k=(2.303)/(t)log""(a)/(a-x)=(2.303)/(t)log""(P_(0))/(2P_(0)-P_(t))`
When `t=360" sec,"k=(2.303)/(360" s")log""(350)/(2xx35.0xx54.0)=(2.303)/(360" s")log""(35)/(16)=(2.303)/(360" s")(0.3400)=2.175xx10^(-3)s^(-1)`
When `t=720" sec,"k=(2.303)/(720" s")log""(35.0)/(2xx35.0-63.0)=(2.303)/(720" s")log5=(2.303)/(720)(0.6990)=2.235xx10^(-3)s^(-1)`
`:." Average value of "k=(2.175+2.235)/(2)xx10^(-3)s^(-3)=2.20xx10^(-3)s^(-1).`
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