The decomposition of `A` into product has value of `k` as `4.5xx10^(3)s^(-1)` at `10^(@)C` and energy of activation of `60kJmol^(-1)`. At what temperature would `k` be `1.5xx10^(4)s^(-1)?`

Explanation

`k_(1)=4.5xx10^(3)s^(-1),T_(1)=10+273" K"=283" K",k_(2)=1.5xx10^(4)s^(-1),T_(2)=?,E_(a)=60" kJ mol"^(-1)`
Applying Arrhenius equation,
`log""(k_(2))/(k_(1))=(E_(a))/(2.303" R")((T_(2)-T_(1))/(T_(1)T_(2)))`
`log""(1.5xx10^(4))/(4.5xx10^(3))=(60000" J mol"^(-1))/(2.303xx8.314" JK"^(-1)" mol"^(1))((T_(2)-283)/(283T_(2)))`
or `log3.333=3133.63((T_(2)-283)/(283t_(2)))" or "(0.5228)/(3133.63)=(T_(2)-283)/(283T_(2))" or "0.0472T_(2)=T_(2)-283`
or `0.9528T_(2)=283" or "T_(2)=(283)/(0.9528)=297" K"=297-273""^(@)C=24""^(@)C.`