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The rate law for the following reactions...

The rate law for the following reactions:
`Ester + H^(o+) rarr "Acid" + "Alcohol"`, is
`dx//dt = k(ester)[H_(3)O^(o+)]^(0)`
What would be the effect on the rate if
(a) concentration of ester is doubled.
(b) concentration of `H^(o+)` ion is doubled.

Text Solution

Verified by Experts

(i) The rate of reaction will be doubled. (ii) No effect on rate.
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